Question

Consider the composition of a 3-child family in which the children were born at different with both genders are equally likely at each birth. What is the probability that the oldest child and the youngest child are of the same gender?​

Answer 1

Step-by-step explanation:

verify that matrix A satisfies its characteristic equation and find A-l for A= [1 2 1

0 1 -1

3 -1 1]

Answer 2

Answer:

1/2

Step-by-step explanation:

S = both children are of the same gender or of different genders

N( S ) = 2 ( 2 genders)

E = both the children are of the same gender

N( E ) = 1 (any one gender)

P(E) = N(E)/N(S)

=1/2

Therefore the probability is 1/2