Consider the displacement of an SHM is
given by x=5cos(2Tt+4). The velocity
amplitude is given by
Answers
Answered by
0
Answer:
x=Asin(2πt+
3
π
)
Velocity is maximum at mean position i.e. x=0
⇒sin(2πt+
3
π
)=0
⇒(2πt+
3
π
)=0,π,2π,3π....
if we take (2πt+
3
π
)=0, time will come negative which is not possible. So we take (2πt+
3
π
)=π
⇒t=
3
1
s=0.33s
for other solutions, we will get higher values of time. but Since it is asking for the first time after t=0, the required solution will be t=0.33s
Similar questions