Chemistry, asked by HRUDAYA8, 6 months ago

Consider the elements in the second period and p-block. The first
lonization energy (of these elements)
Increases steadily from B to Ne
Decreases steadily from B to Ne
Increases from B to O, decreases for F and then increases for Ne
Increases steadily from B to N, decreases for O and increases from O to Ne​

Answers

Answered by Anonymous
10

Answer:

Be′ and ′N′ comparatively more stable valence subshell than 'B' and 'O'.

Hence, the correct order of first ionisation enthalpy is:

\large\rm {Li<B<Be<C<O<N<F<Ne}

Answered by Anonymous
1

Answer:

Be′ and ′N′ comparatively more stable valence subshell than 'B' and 'O'.

Be′ and ′N′ comparatively more stable valence subshell than 'B' and 'O'. Hence, the correct order of first ionisation enthalpy is:

Be′ and ′N′ comparatively more stable valence subshell than 'B' and 'O'. Hence, the correct order of first ionisation enthalpy is:

Be′ and ′N′ comparatively more stable valence subshell than 'B' and 'O'. Hence, the correct order of first ionisation enthalpy is: Li<B<Be<C<O<N<F<Ne

Similar questions