Science, asked by dipeshlamba406, 10 months ago

Consider the elements present in the given box.
Ca, O. CI, Na, Mg, C
The total number of element(s) that form(s)
divalent cation is
(1) 1
(2) 2
(3) 3
(4) 4
AANLEIL__I_
min
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Answers

Answered by Siddharth1709

3

Answer:

2

O,Cl

Explanation:

Answered by tejpratap12075

1

Answer:

3 is your question answer

....

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