Question

consider the eq ydx+xdy-dz/z^3=0 then

Answer 1

Step-by-step explanation:

ydx+xdy-dz/z³=0

ydx+xdy=dz/z³

Now,If you know that

d(x.y)= xdy+ydx

then

d(x.y)=dz/z³ integrate both sides

x.y=-1/2z²+C where C is constant