Question

consider the equation as shown (x-a)(y-b)=(x-2a)(y-b/2)

Answer 1

Answer:

2x²-2xy-bx-2ay+4ab=0

Step-by-step explanation:

(x-a)(y-b) = (x-2a)(y-b/2)

x²-bx-ay+ab = xy-bx/2-2ab+ab

x²-bx/2-ay = xy-2ab

2x²-bx-2ay = 2xy-4ab

2x²-2xy-bx-2ay+4ab=0