consider the equation as shown (x-a)(y-b)=(x-2a)(y-b/2). on comparing the coefficients , a student says
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xy-bx-ay+ab=xy-bx/2-2a/y+ab
coefficients of x=-b=-b/2
2b=b
2b-b=0
b=0
coefficients of y=-a=-2a
2a-a=0
a=0
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