Question

consider the equation of the line 3x-4y+10=0
find its:
slope
x and y intercepts

Answer 1

3x-4y+10=0
Now we separate the y and rest of the term in the format:
y=mx+c
where, 
m = slope, c= y-intercept
-4y=-3x-10  [ Take minus common and cancel it]
4y=3x+10
$y= \frac{3}{4}$ x + $\frac{10}{4}$
y=$\frac{3}{4}x+ \frac{5}{2}$

So,
The slope of the line= $\frac{3}{4}$
and
y-intercept = $\frac{5}{2}$

Answer 2

Slope is - ( coefficient of x ) / coefficient of y
= - 3/-4
= 3/4
 Hence slope is 3/4
To find y intercept put x = 0
 -4y+10=0
4y=10
2y=10
Y=5/2