Consider the equation x ^ 2 - 4x + 7 - k = 0 and find the value of k, if the roots of the equation are real and equal.
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Answered by
2
Answer:
x
2
−4x+k=0 is of the form ax
2
+bx+c=0 where a=1b=−4c=k
Roots are equal⇒ Discriminant=0
⇒b
2
−4ac=0
⇒(−4)
2
−4×1×k=0
⇒16−4k=0
⇒−4k=−16
∴k=
4
16
=4
Step-by-step explanation:
Hopes it help u
Answered by
0
Answer:
Nature of the roots is real and equal
Let the x be 0
0^2 - 4(0) + 7 - k = 0
0 - 0 + 7 - k = 0
7 - k = 0
- k = - 7
Therefore k = 7
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