Question

consider the equation x^2+px+q=0. if the roots of this equation differ by 2, then q equals​

Answer 1

Answer:

Step-by-step explanation:

Hi Mate!!!

Let the roots be a and b

a - b = 1. as given roots differ by unity

a + b = p

ab = q

a - b = √ {( a+b)² - 4ab}

1 = √{ ( -p)² - 4( q ) }

Squaring both sides

p² = 1+4q. hence, proved

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