Question

Consider the experiment of throwing a die, if a multiple of 3 comes up, throw the
die again and if any other number comes, toss a coin. Find the conditional probability
of the event the coin shows a tail, given that at least one die shows a 3​

Answer 1

Answer:

Step-by-step explanation:

since multiples of 3 are = 2 (6 and 3)

probability of multiple of 3 will be = 1/2

not multiple = 1/2

if not multiple then= coin show tail have a probability 1/2

so the probability of showing tail would be 1/2+1/2=1

and that of multiple of 3 will be =1+1/2=3/2