Physics, asked by trishabh9145, 4 hours ago

Consider the ff: 2CuCl2 + 4Kl→2Cul + 4 KCl + I2
Cu=63.54g/mol Cl=35.45g/mol
I=126.90g/mol K=39.10g/molg
a.When 0.56 grams of CuCl2 reacts with 0.64 grams of Kl, how many grams of I2 are formed?
b. What is the limiting reactant?

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Answered by psatharv50

0

Answer:

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