Consider the figure below. The current through 6 ohm resistor is 4A in the direction shown. What are the currents through the 25 ohm and 20 ohm resistors?
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Solution
From Ohm's law, the voltage drop across the 6Ω resistor is
V=IR=(4A)(6Ω)=24V
The voltage drop across the 8Ω resistor is the sum of these two currents i.e., :7 A. The voltage drop across the 25Ω resistor is
V=IR=(7A)(25Ω)=175V
Total voltage drop across the top branch of the circuit is: 175+24 = 199V
Which is also the voltage drop across the 20Ω
resistor.
The current through the 20Ω resistor is then
I=V/R=199V/20Ω=9.95A
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