Consider the following cell reaction
2Fe + O2 + 4H (2) ► 2Fe2(aq) + 2H,00;
E = 1.67V
At [Fe *) = 10 M. Po, = 0.1 atm and pH = 3
the cell potential at 25°C is
1.57 V
2.67 V
1.47 V
2.27 V
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Answer:
2.27 voltages
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2.27 is your answer
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