Consider the following equation of motion and re write them for a free falling body v=u+at s=ut+1/2 at square
jbdesai123:
do you have bit paper
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Answered by
1
For a free fall body accelration of Body becomes equal to acceleration due to gravity so we will replace a by g
so. v= u+ gt
so. v= u+ gt
Answered by
4
In this case "a" becomes "g"
therefore v=u+at become v=u+gt
here u initial velocity is zero in freely falling body
v=0+gt
v=gt
in s=ut+1/2at^2
s=ut+1/2gt^2
s=0*t+1/2gt^2
s=1/2gt^2
therefore v=u+at become v=u+gt
here u initial velocity is zero in freely falling body
v=0+gt
v=gt
in s=ut+1/2at^2
s=ut+1/2gt^2
s=0*t+1/2gt^2
s=1/2gt^2
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