Consider the following formula: A = B + 3 (4 - C) If B equals 5 and C equals 2, what is the value of A?
Answers
Answered by
2
B+3 (4-C) = A
B= 5 , C = 2
B+3 (4 - C) = A
step 1 ) 5+3 (4- 2) = A
step 2 : we will open the brackets)
5 + 12 - 6 = A (we multiplied 3 with 4 and -2 )
step 3 ) 17- 6 = A
step 4) 11 = A
verification :
LHS : (left hand side)
B = 5 , C = 2
5 + 3 (4 - 2)
5 + 3 x 2
5 + 6 = 11
RHS : (right hand side)
A = 11
LHS = RHS
11 = 11
hence verified
B= 5 , C = 2
B+3 (4 - C) = A
step 1 ) 5+3 (4- 2) = A
step 2 : we will open the brackets)
5 + 12 - 6 = A (we multiplied 3 with 4 and -2 )
step 3 ) 17- 6 = A
step 4) 11 = A
verification :
LHS : (left hand side)
B = 5 , C = 2
5 + 3 (4 - 2)
5 + 3 x 2
5 + 6 = 11
RHS : (right hand side)
A = 11
LHS = RHS
11 = 11
hence verified
Answered by
0
The value of A is 11.
Step-by-step explanation:
The given equation is A = B + 3(4 - C)
Also, it is given that the value of B = 5 and C = 2
Substituting the value of B and C in the equation, we obtain,
A = B + 3(4 - C)
A = 5 + 3(4 - 2)
First solving the terms in the bracket, we get,
A = 5 + 3(2)
Now 3 can be multiplied by 2, we get,
A = 5 + 6
Finally adding the numbers,
A = 11
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