Math, asked by Sindhudevi2351, 11 months ago

consider the following frequency distribution of the height of 60 students of a class:
Height no of students
150-155 15
155-160 13
160-165 10
165-170 8
170-175 9
175-180 5
The sum of the lower limit of the modal class and the upper limit of the median class is :
A ) 310
B ) 315
C ) 320
D ) 330

Answers

Answered by wwefanclub078
137

Modal class = 150-155

So, lower limit of modal class is 150.


Now,


Height No. of Cumulative

students Frequency

150-155 15 15

155-160 13 28

160-165 10 38

165-170 8 46

170-175 9 55

175-180 5 60


Total (n) = 60

n/2 = 30


Median class = 160-165

So, upper limit of median class = 165


Sum of the lower limit of the modal class and upper limit of the median class = 150 + 165

= 315


Answer is (B) 315


Answered by amitnrw
13

Given : frequency distribution of the heights of 60 students of a class

Height       150-155 155-160 160-165 165-170 170-175 175-180

No of  students  15      13             10         8              9            5

To Find : The sum of the lower limit of the modal class and the upper limit of the median class is :

A ) 310

B ) 315

C ) 320

D ) 330

Solution:

Height(in cm)  number of students    CF

150-155          15                                    15

155-160           13                                   28

160-165          10                                   38

165-170           8                                    46

170-175           9                                    55

175-180          5                                    60

Total Frequency = 60

60/2 = 30

which lies between 160-165

Median class is 160-165

upper limit of the median class in the given data is   165  

Max frequency 15 in class 150-155

Hence Modal class is 150-155

lower limit of the modal class  = 150

The sum of the lower limit of the modal class and the upper limit of the median class is : 150 + 165 = 315

B ) 315  is correct answer

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