Question

Consider the following frequency distribution of the heights of 60 students of a class
170-175
165-170
175-180
155-160
150-155
| 160-165
Height (in
cm)
13
10
15
No of
students
The upper limit of the median class in the given data is
a) 165
b) 155
c) 160
d) 170


........Tell with the reason also........​

Answer 1

Answer:

Option A is correct

Step-by-step explanation:

The data of question is incomplete.I collected the complete data.Now the solution is shown below:

$\begin{tabular}{|c|c|c|} \cline{1-3} \textbf{Height in cm} & \textbf{Number of students (f)} & \textbf{Cumulative Frequency (CF)} \\ \cline{1-3} 150-155 & 15 & 15 \\ \cline{1-3} 155-160 & 13 & 28 \\ \cline{1-3} \bold{160-165} & \bold{10} & \bold{38} \\ \cline{1-3} 165-170 & 8 & 46 \\ \cline{1-3} 170-175 & 9 & 55 \\ \cline{1-3} 175-180 & 5 & 60 \\ \cline{1-3} Total & 60 & \\ \cline{1-3} \end{tabular}$

We know that to find Median class,First find n/2

here n/2 = 30

To find the median class ,look for that class which is near to 30,but not less than 30.

So,Median class = 160-165

Upper limit of Median class is 165.

Hope it helps you.

Answer 2

Answer:

We know that to find Median class,First find n/2

We know that to find Median class,First find n/2here n/2 = 30

We know that to find Median class,First find n/2here n/2 = 30To find the median class ,look for that class which is near to 30,but not less than 30.

We know that to find Median class,First find n/2here n/2 = 30To find the median class ,look for that class which is near to 30,but not less than 30.So,Median class = 160-165

We know that to find Median class,First find n/2here n/2 = 30To find the median class ,look for that class which is near to 30,but not less than 30.So,Median class = 160-165Upper limit of Median class is 165.

We know that to find Median class,First find n/2here n/2 = 30To find the median class ,look for that class which is near to 30,but not less than 30.So,Median class = 160-165Upper limit of Median class is 165.Hope it helps you.