Math, asked by Shruti2822, 11 months ago

Consider the following frequency distribution of the heights of 60 students of a class
Height(in cm)/number of students
150-155 / 15
155-160 / 13
160-165 / 10
165-170 / 8
170-175 / 9
175-180 / 5
The upper limit of the median class in the given data is
(a) 165
(b) 155
(c) 160
(d) 170

Answers

Answered by hukam0685
219

Answer:

Option A is correct,Upper limit of Median class is 165.

Step-by-step explanation:

 \begin{tabular}{|c|c|c|} \cline{1-3} \textbf{Height in cm} & \textbf{Number of students (f)} & \textbf{Cumulative Frequency (CF)} \\ \cline{1-3} 150-155 & 15 & 15 \\ \cline{1-3} 155-160 & 13 & 28 \\ \cline{1-3} \bold{160-165} & \bold{10} & \bold{38} \\ \cline{1-3} 165-170 & 8 & 46 \\ \cline{1-3} 170-175 & 9 & 55 \\ \cline{1-3} 175-180 & 5 & 60 \\ \cline{1-3} Total & 60 & \\ \cline{1-3} \end{tabular}

We know that to find Median class,First find n/2

here n/2 = 30

To find the median class ,look for that class which is near to 30,but not less than 30.

So,Median class = 160-165

Upper limit of Median class is 165.

Hope it helps you.

Answered by dhruvkoul
109

Answer:

b) 165

Step-by-step explanation:

n/2 = 30

To find the median class ,look for that class which is near to 30,but not less than 30.

So,Median class = 160-165

Upper limit of Median class is 165

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