Math, asked by ajayramdasi38, 2 months ago

Consider the following list of 15 large numbers:
4250081908400271013963777660
4250881908400271013963777661
4250081908400271013963777667
4250081908400271013963777663
4250081908400271013963777662
a
5250081908400271013963777668
5250081908400271013963777662
5250081908400271013963777667
5250081908400271013963777661
5250081908400271013963777666
6250081908400271013963777663
can0100010077107 2052777542
Please compute the average of these numbers​

Answers

Answered by shyamrathod2k
0

Answer:

5250081908400271013963777664

Step-by-step explanation:

4250081908400271013963777660  +  0  +  0

4250081908400271013963777660  +  1  +  0

4250081908400271013963777660  +  7  +  0

4250081908400271013963777660  +  3  +  0

4250081908400271013963777660  +  2  +  0

4250081908400271013963777660  +  8  + 1000000000000000000000000000

4250081908400271013963777660  +  2  + 1000000000000000000000000000  

4250081908400271013963777660  +  7  + 1000000000000000000000000000  

4250081908400271013963777660  +  1  + 1000000000000000000000000000  

4250081908400271013963777660  +  6  + 1000000000000000000000000000  

4250081908400271013963777660  +  3  + 2000000000000000000000000000  

4250081908400271013963777660  +  3  + 2000000000000000000000000000

4250081908400271013963777660  +  8  + 2000000000000000000000000000

4250081908400271013963777660  +  9  + 2000000000000000000000000000

4250081908400271013963777660  +  2  + 2000000000000000000000000000

===============================================================

4250081908400271013963777660*15 + 62 + 15*1000000000000000000000000000

so average is

(4250081908400271013963777660*15 + 62 + 15*1000000000000000000000000000)/15

= 4250081908400271013963777660+ 4 + 1000000000000000000000000000

= 5250081908400271013963777664

Answered by arshikhan8123
0

Concept:

In statistics, in addition to the mode and median, the mean is one of the measures of central tendency. Simply put, the mean is the average of the values in the given set. It indicates that values in a particular data set are distributed equally. The three most frequently employed measures of central tendency are the mean, median, and mode. The total values provided in a datasheet must be added, and the sum must be divided by the total number of values in order to determine the mean. When all of the values are organised in ascending order, the Median is the median value of the given data. While the number in the list that is repeated a maximum of one time is the mode.

Given:

Consider the following list of 15 large numbers:

4250081908400271013963777660

4250881908400271013963777661

4250081908400271013963777667

4250081908400271013963777663

4250081908400271013963777662

5250081908400271013963777668

5250081908400271013963777662

5250081908400271013963777667

5250081908400271013963777661

5250081908400271013963777666

6250081908400271013963777663

Find:

Average of the numbers

Solution:

1st number:4250081908400271013963777660  +  0  +  0

2nd number:4250081908400271013963777660  +  1  +  0

3rd number:4250081908400271013963777660  +  7  +  0

4th number:4250081908400271013963777660  +  3  +  0

5th number:4250081908400271013963777660  +  2  +  0

6th number:4250081908400271013963777660  +  8  +1000000000000000000000000000

7th number:4250081908400271013963777660  +  2  + 1000000000000000000000000000  

8th number:4250081908400271013963777660  +  7  + 1000000000000000000000000000  

9th number:4250081908400271013963777660  +  1  + 1000000000000000000000000000  

10th number:4250081908400271013963777660  +  6  + 1000000000000000000000000000  

11th number:4250081908400271013963777660  +  3  + 2000000000000000000000000000  

12th number:4250081908400271013963777660  +  3  +2000000000000000000000000000

13th number:4250081908400271013963777660  +  8  +2000000000000000000000000000

14th number:4250081908400271013963777660  +  9  +2000000000000000000000000000

15th number:4250081908400271013963777660  +  2  + 2000000000000000000000000000

Sum of all numbers=4250081908400271013963777660*15 + 62 +15*1000000000000000000000000000

So the average is calculated by breaking the larger no. into three parts for easier calculation

(4250081908400271013963777660*15 + 62 + 15*1000000000000000000000000000)/15

= 4250081908400271013963777660+ 4 + 1000000000000000000000000000

= 5250081908400271013963777664

Therefore, the mean of all the numbers is = 5250081908400271013963777664

#SPJ3

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