Question

Consider the following min-term expansion.
F(x, y, z)=11(3,4,5,6,7)
Find the Boolean expression for F(x, y, z).
(a) F(x, y, z) = x+y =
(b) F(x, y, z)= r': v'+r.;'
(C) F(x, y, z) = x':
(d) F(x, v.2) = x + y +='
Answer
A
B
C
D​

Answer 1

Answer:

A

Step-by-step explanation:

F(X,Y,Z)=11(3,4,5,6)

F=X+Y=3+4=7X+Y

F=Y-Z+X

Where in first X=3,Y=4

second x=5,Y=4,z=6

so F=(x, y, z)=x+y