Question

Consider the following network of six identical

resistors. If the equivalent resistance of this circuit

between A and B, B and C, and A and C are RAB,

RBC and RAC respectively then which of the following

relations is correct? [1]

(a) RAB = RBC > RAC

(b) RAC > RBC > RAB

(c) RAB = RBC = RAC

(d) RBC > RAC > RAB​

Answer 1

Considering the following network of six identical  resistors. If the equivalent resistance of this circuit  between A and B, B and C, and A and C are RAB,  RBC and RAC respectively then RAC > RAB > RBC which of the following  relations is correct?

• None of the given options are correct.
• From given figure, we have,
• RAB = R   (as there is only one resistor between A and B)
• RBC, here, 2 resistors are in parallel between B  and C.
• ∴ 1/RBC = 1/R + 1/R = 2/R
• ⇒ RBC = R/2
• RAC, here there are 3 resistor, 2 are in parallel and the other one is in series with them.
• ∴ RAC = R + 1/[1/R + 1/R] = R + R/2
• ⇒ RAC = 3R/2
• as, 3R/2 > R > R/2
• we have, RAC > RAB > RBC

Answer 2

Explanation:

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