Question

consider the following number pattern using only the odd natural numbers and so on...
numbers A B are taken from
C
the pattern ,where A,B are two adjacent numbers in a certain row ,and C is the number in the next row,directly below ,and between , A and B.
if A+B+C =2093,find value of C

plz refer to the attach ment and answer it with explanation
(marked as brainliest)​

Answer 1

Answer:

679, 681, 733

Step-by-step explanation:

the middle number of row (x) = x² (if x is odd)

                                                 =x²-1 and x²+1 (if x is even)

total numbers in row (x) = x

sum of numbers in the  row (x) =  x³

(A+B+C)/3=2093/3= 697.67 is close to B

$\sqrt{B}$ = 26.413 ≈≈26  is the no of row of A and B, 27 of C

the middle numbers of row 26 & 27 are (675, 677) and 729 respectively

let, B = 677 + n, so, A= 677-2+n,  C = 729 +n

so, 677+n+677-2+n+729+n=2093

so, 2081 + 3n = 2093

so, n= 4

A = 677-2+4= 679,

B= 677 +4 = 681,

C =729+4 = 733