Question

Consider the following organic compounds:

ethane C2H6 (CH3CH3)
ethanol C2H6O (CH3CH2OH)
ethanoic acid C2H4O2 (CH3COOH)
methoxymethane C2H6O (CH3OCH3)
octane C8H18
octan-1-ol C8H18O (CH3CH2CH2CH2CH2CH2CH2CH2OH)
1. Rank the four compounds containing two carbons from lowest to highest boiling point. Explain your reasoning using intermolecular forces in your answer.

2. Of the four compounds containing two carbons, which is the most soluble in water? Explain your reasoning using intermolecular forces in your answer.

3. Between ethanol and octan-1-ol: Which compound is more polar? Explain your answer using intermolecular forces in your answer.

4. Which class of organic compounds would be the most soluble in non-polar compounds? Explain your reasoning using intermolecular forces.

5. Explain why the boiling point of ethanol is different from the boiling point of octan-1-ol. Use intermolecular forces in your answer.

6. Compare the flashpoint of methane to octane, methanol to octan-1-ol, and methanoic acid and octanoic acid. Explain your rationale using intermolecular forces.

Answer 1

Answer:

3) ethanol is more polar becoz hydrophobic part is less and thus can be soluble in water , also we know that water is polar and only polar compounds can be soluble (like dissolve like )

4)ethane must be mostly soluble in polar solvent as it has only hydrophobic part in it

5)boiling point of ethanol is less than boiling point of octane-1-ol becoz of less molecular weight

Hope it helps

Explanation: