Consider the following parallelogram ABCD. Find the values of the unknown y and z.
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Answer:
- y = 50°
- z = 50°
Explanation:
Let the point of intersection of the two diagonals AC and BD = O
P.F.A the figure below for reference of angles
Given:
A Parallelogram ABCD in which:
- ∠BCO = 40°
- ∠CBO = y
- ∠BOC = 90°
- ∠ADO = z
To find:
- The value of y and z
Proof:
In ΔBOC,
∠CBO + ∠BCO + ∠BOC = 180° (Angle Sum Property of Δ)
⇒ y + 40° + 90° = 180°
(Given, ∠BCO = 40°, ∠CBO = y, ∠BOC = 90°, ∠ADO = z)
⇒ y + 130° = 180°
⇒ y = 180° - 130°
⇒ y = 50°
Now, y = 50° = z ( When AD || BC and BD is the transversal, Alternate
interior angles are equal )
Hence,
- y = 50°
- z = 50°
Proved.
Hope you got that.
Thank you.
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