consider the following parallelogram. find the value of x,y,z
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in parallelogram angle ADC is equals to angle A B C so y = 112
Now alternative angle A =40
z + 112 +40 = 180
=> z = 28
x and z are also alternative angles so x = 28
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Answer:
B=D(bcoz opposite side of pallelogram are equal)
DAC=ACB=40(alternate angles)
In triangle ADC
D+DAC+DCA=180(angle sum property)
112+40+X=180
X=180-152
X=28
X=z=28(alternate angles)
hence angle X and z are 28 degree
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