Chemistry, asked by muavvizakhtar270901, 4 months ago

Consider the following processes :
∆H (kJ/mol)
1/2 A → B +150
3B → 2C + D –125
E + A → 2D +350
For B + D → E + 2C, ∆H will be :
(a) 525 kJ/mol (b) – 175 kJ/mol
(c) – 325 kJ/mol (d) 325 kJ/mol​

Answers

Answered by bhumiwashnikar
4

Explanation:

Hope this ans.. may help you

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Answered by mirpervaiz2
0

Answer:

--175 is the correct answer....

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