Consider the following PV diagram for a monoatomic gas. The ratio of work done by the gas to the change in internal energy of the gas will be A) 1:3 B) 3:1 C) Zero D) 1:1
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The ratio of work done by the gas to the change in internal energy of the gas will be 3:1
Therefore, option (B) is correct.
Explanation:
The figure is attached.
At initial point from ideal gas equation
or,
At initial point
At final point
Change in internal energy
Work done by the gas in expansion
Ratio of work done to the change in internal energy
Hope this answer is helpful.
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Q: A mono atomic ideal gas sample is given heat Q. One half of this heat is used as work done by the gas and rest is used for increasing its internal energy. The equation of process in terms of volume and temperature is ?
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