consider the following ratio
a+b = e : Kc =2
2b + 2c = 2d : Kc =4
what will be the equilibrium constant Kc for a+d =e+c
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Answer:
A+B⇌E;K
c
=6
2B+C⇌2D;K
c
=4
What will be the equilibrium constant (K
c
) for the following reaction?
A+D⇌E+
2
1
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