Chemistry, asked by ahmedsiam5830, 3 months ago

Consider the following reaction:


H 2 (g) + I 2 (g) = 2 HI (g)


The equilibrium constant K c for the reaction of H 2 with I 2 at 700K is 57.0. If 1.0

mol of H 2 and 1.0 mol of I 2 react in a 10.0L reaction vessel, what are the

concentrations of H 2 , I 2 and HI at equilibrium? What is the composition of

equilibrium mixture in moles? Plot a concentration vs. time diagram for the

above chemical equation.

Answers

Answered by rollijoh111
0

Answer:

H 2 (g) + I 2 (g) = 2 HI (g)

The equilibrium constant K c for the reaction of H 2 with I 2 at 700K is 57.0. If 1.0

mol of H 2 and 1.0 mol of I 2 react in a 10.0L reaction vessel, what are the

concentrations of H 2 , I 2 and HI at equilibrium? What is the composition of

equilibrium mixture in moles? Plot a concentration vs. time diagram for the

above chemical equation.

Explanation:is it corect

Answered by saurabhtawale2003
0

Explanation:

N2 (g) + 3H2 (g) ⇔ 2 NH3 (g). The Haber process consists of putting together N2 and H2 in a high pressure tank in the ... At 448°C the Kc for the reaction H2(g) + I2(g) ⇔ 2HI (g) is 51 .

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