Question

Consider the following reaction: Xe(g)+2F2(g)→XeF4(g). A reaction mixture initially contains 2.24 atm Xe and 4.27 atm F2. lf the equilibrium pressure of Xe is 0.34 atm, how do you find the equilibrium constant (Kp) for the reaction?

Answer 1

The average xe-f bond energy is 34kcal/mol,first i.e of xe is 279kcal/mol'electron affinity of f is 85kcal/mol &bond dissociation energy of f2 is 38kcal/mpl. then the enthalpy change for the reaction xef4------> xe+ + f-+f2+f