Chemistry, asked by ttgarg59271, 11 months ago

Consider the following reactions:
(i) H⁺(aq) + OH⁻(aq) → H₂O(l),
∆H = – X₁ kJ mol⁻¹
(ii) H₂(g) + 1/2 O₂(g) → H₂O(l),
∆H = – X₂ kJ mol⁻¹
(iii) CO₂(g) + H₂(g) → CO(g) + H₂O,
∆H = – X₃ kJ mol⁻¹
(iv) C₂H₂ (g) 5/2 O₂ (g) → 2CO₂(g) + H₂O(l),
∆H = + 4X₄ kJ mol⁻¹
Enthalpy of formation of H₂O (l) is
(a) + X₃ kJ mol⁻¹ (b) – X₄ kJ mol⁻¹
(c) + X₁ kJ mol⁻¹ (d) – X₂ kJ mol⁻¹

Answers

Answered by Anonymous
1

\huge\bold\red{Answer:-}

(a) + X₃ kJ mol⁻¹

Answered by ItzSmartyYashi
2

\huge{\underline{\mathbb{\red{Answer}}}}

(a) + X₃ kJ mol⁻¹

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