Question

Consider the following reactions
N2 +202 =2NO2 AH = 92kJ
2NO+O2 2NO2 AH=-158kJ
Calculate the enthalpy of reaction of NO
N2+O2 2NO
ΔΗ =
A) 250
B)-250
kJ
C) -66
D) +660

Answer 1

Answer:

N2(g) + O2(g) 2NO(g). ΔH3 = +181 kJ mol–1. Looking at the target equation, we need 1 mole of N2O(g) as the reactant. ... the enthalpy change of formation of zinc sulphide is –204 kJ mol ... b) ΔH1 represents the enthalpy change of combustion of C(graphite) and the enthalpy ... [8(–394) + 9(–286) – (–250)] kJ mol–1.

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