Chemistry, asked by nehaliganvit3, 1 month ago

Consider the following reversible reaction. In a 2.0 litre container, the following amount was found in equilibrium at 400 °C. 0.042 moles N2, 0.516 moles H2 and 0.0357 moles NH3. Evaluate Kc. N2(g) + 3H2 (g) ⇌ 2NH3(g). *
• 0.878
• 1.99
• None of these
• 4.94​

Answers

Answered by syedarshin
1

Answer:

b. 1.99

Explanation:

a 3.00 liter container, the following amounts are found in eq… ... and 0.0357 mole NH3. Evaluate Kc.N2(g) + 3H2(g) 2NH3(g). 2 ... 400°C. 0.0420+3×0.516+2× 0.0357.

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