Consider the following statement , 2^4^2 = (2^4)^2
Is the above statement correct ? Show calculations
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Step-by-step explanation:
Given,
4(x−p)(x−q)−r
2
=0
4x
2
−4xq−4xp+4pq−r
2
=0
4x
2
−(4q+4p)x+4pq−r
2
=0
x=
2⋅4
−(−4q−4p)±
(−4q−4p)
2
−4⋅4(4pq−r
2
)
upon solving the above equation, we get,
x= 2
q+p± p 2 −2pq+r 2 +q 2
x=
2
q+p±
(p−q)
2
+r
2
Now it can be observed that discriminant of the given quadratic equation will always be positive. Thus roots of the given quadratic equation are real.
Also if p=q nad r=0, then discriminant becomes zero, thus quadratic equation will have equal roots if p=q and r=0.
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