Question

Consider the following transformations :
CH₃COOH □(→┴(CaCO₃) ) A □(→┴(heat) ) B □(→┴(I₂) ) C
The molecular formula of C is
OH
|
(a) CH₃ — C — CH₃
|
I
(b) ICH₂ — COCH₃
(c) CHI₃ (d) CH₃I

Answer 1

I think the correct answer is (c)

Answer 2

CHI₃ or iodoform will be formed.

Explanation:

• The reaction is a simple haloform reaction.

• Here the acetic acid is first reacted with calcium carbonate which forms the product calcium acetate and carbon dioxide.

• So product A is calcium acetate.

• The calcium acetate when heated forms calcium carbonate and acetone.

• So product B is acetone.

• As the acetone is reacted with iodine in NaOH, it forms iodoform.

• So product C is iodoform.

For more information about haloform reaction,

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A ketone A which undergoes haloform reaction gives a compound B on reduction . B on heating with sulphuric acid gives a compound C which forms monoozonide D. D onhydrolysis in the presence of zinc dust gives only acetaldehyde. identify A, B, C, and D. write down the reactions involved.

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Why acetic acid does not show haloform reaction? - Brainly.in