Question

① Consider the frequency distribution table given below which gives the weights of 38 students of a class Weight (in kg) 31 – 35 36 – 40 41 – 45 46 – 50 51 – 55 56 – 60 61 – 65

Number of students 9 5 14 3 2 1 4

1. Find the probability that the weight of a student in the class lies in the interval (46 - 50) kg.

2. Find the probability that weight of a student is more than 50 kg.



② To know the opinion of the students about the game football, a survey of 200 students was conducted. The data

is recorded in the following table:

Opinion Like Dislike

Number of students 135 65

Find the probability that the student chosen at random (i) likes football (ii) does not like football.​

Answer 1

Step-by-step explanation:

Given that:

Weight (in kg) 31 – 35 36 – 40 41 – 45 46 – 50 51 – 55 56 – 60 61 – 65

Number of students 9 5 14 3 2 1 4

To find:

1. Find the probability that the weight of a student in the class lies in the interval (46 - 50) kg.

2. Find the probability that weight of a student is more than 50 kg.

Solution:

1) Probability of an event is

Favourable outcomes/Total Outcomes

Favourable outcomes for weight (46-50)kg:3

Total students of the class(total outcome):38

Probability that the weight of a student in the class lies in the interval (46 - 50) kg=3/38

2)Probability of an event is

Favourable outcomes/Total Outcomes

Favourable outcomes for weight more than 50 kg:2+1+4=8

Total students of the class(total outcome):38

Probability that the weight of a student in the class more than 50kg=8/38=4/19

Given:

To know the opinion of the students about the game football, a survey of 200 students was conducted. The data

is recorded in the following table:

Opinion Like Dislike

Number of students 135 65

To find:Find the probability that the student chosen at random (i) likes football (ii) does not like football.

Solution:

1) Likes football:

Probability of an event is=

Favourable outcomes/Total Outcomes

Favourable outcomes:135

Total Outcomes:200

P(E)=135/200

=27/40

2)Dislikes football:

Probability of an event is=

Favourable outcomes/Total Outcomes

Favourable outcomes:65

Total Outcomes:200

P(E1)=65/200

=13/40

Hope it helps you.

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