Question

consider the function f(x)=x^3-2x^2-x+1​

Answer 1

Answer:

f(−2)=f(3)=0

F(x) is continuous in [−2,3] & derivable in (−2,3) so Rolles theorem is applicable.

So ∃cϵ(−2,3) such that f‘(c)=0

⇒

(c−1)

2

2c

3

−5c

2

+4c−1

=0

After solving this, we get

⇒c=

2

1