Question

consider the graph of two linear equations ax+by=c and bx-ay=c where a, b and c are all greater than zero. these graphs are​

Answer 1

Concept:

If the product of slopes of two straight lines is -1, then the lines are perpendicular to each other.

Given equations are

ax+by-c=0

bx-ay-c=0

We know that any equation of the form ax+by+c=0 always represents a straight line.

Therefore the given two equations represent straight lines.

$\text{slope of ax+by-c=0 is }\bf\,m_1=\frac{-a}{b}$

$\text{slope of bx-ay-c=0 is }m_2=\frac{-b}{-a}$

$\implies\bf\,m_2=\frac{b}{a}$

Now,

$m_1\times\,m_2$

$=\frac{-a}{b}\times\,\frac{b}{a}$

$=-1$

$\therefore\text{The given lines are perpendicular to each other}$

Answer 2

Answer:

zeros , this may help you