Question

Consider the hydrated ions of Ti²⁺, V²⁺, Ti³⁺ and Sc³⁺. The correct order of their spin-only magnetic moments is:
(A) Ti³⁺ < T²⁺ < Sc³⁺ < V²⁺ (B) Sc³⁺ < Ti³⁺ < Ti² < V²⁺
(C) V²⁺ < Ti²⁺ < Ti³⁺ < Sc³⁺ (D) Sc³⁺ < Ti³⁺ < V²⁺ < Ti²⁺

Answer 1

Answer:B

Explanation:

Answer 2

Thus the correct order is Sc^3+ < Ti^3+ < Ti 2+ < V 2+

Explanation:

Ti  2+  =1s^2,  2s^2,  2p^6,  3s^2 , 3p^ 6 , 3d^2

 Unpaired electrons =2

Spin only magnetic moment (μ) = √2(2+2) = √8 B.M

Ti  3+  =1s^2,  2s^2,  2p^6,  3s^2 , 3p^ 6 , 3d^1

Unpaired electrons = 1

Spin only magnetic moment (μ) = √1(1+2) = √3 B.M

V  2+  = 1s^2,  2s^2,  2p^6,  3s^2 , 3p^ 6, 3d^3

μ = √3(3+2) = √15 B.M

Sc 3+ = 1s^2,  2s^2,  2p^6,  3s^2 , 3p^ 6

μ = 0

Thus the correct order is Sc^3+ < Ti^3+ < Ti 2+ < V 2+