Question

consider the letters of the word MONDAY. How many permutations of four different letters can be chosen if at least one vowel (a or 0) must be usedconsider the letters of the word MONDAY. How many permutations of four different letters can be chosen if at least one vowel (a or 0) must be used

Answer 1

Answer:

336

Step-by-step explanation:

There are two possibilities

1. Only one vowel is included

2. Two vowels are included

The word MONDAY has 2 vowels & 4 consonants.

For first case:

4c3 × 2c1 × 4! = 192

For the second case:

4c2 × 2c2 × 4! = 144

Total permutation number:

192+144 = 336

Answer 2

Answer:

Step-by-step explanation:

336