Question

Consider the linear equation x+2y=8, Find the point on the line where abscissa is twice the value of the ordinate

Answer 1

Answer:

first let absicca be x and ordinate be y and then solve it

Answer 2

Answer:

the point is (4, 2)

Step-by-step explanation:

we have, x+2y=8

by putting the value of y is 2

so, x+2(2)=8

x+4=8

or x=8-4

or x=4

So,the point is (4,2) ,where abscisa is 2 times the co-ordinate.