Math, asked by Anonymous, 4 months ago

Consider the magnetic flux density \large\rm { B = \frac{\mu_{o} I}{2 \pi r} \hat{\phi}} produced by current I flowing along x axis. what is the \large\rm { \varepsilon} of a sqaure loop C with a area 4m² moving on x-y plane with edges parallel to x- and y-axes, if its center is located at y = 2t m as a function of time?

Compute the emf first as \large\rm{- \frac{d \Psi}{dt}} and then as \large\rm { \displaystyle\oint_{C} \bold{ (V \times B ) } \cdot d \ell}

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Answered by Anonymous
14

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\large\rm

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Answered by sp7227730
2

Answer:

Consider the magnetic flux density \large\rm { B = \frac{\mu_{o} I}{2 \pi r} \hat{\phi}} produced by current I flowing along x axis. what is the \large\rm { \varepsilon} of a sqaure loop C with a area 4m² moving on x-y plane with edges parallel to x- and y-axes, if its center is located at y = 2t m as a function of time?

Compute the emf first as \large\rm{- \frac{d \Psi}{dt}} and then as \large\rm { \displaystyle\oint_{C} \bold{ (V \times B ) } \cdot d \ell}

Step-by-step explanation:

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