consider the matrix a=[8,-8,-2 4,-3,-2 3,-4,1],then a³-6a²+10a-5i=
a.0 b.i+a c.i-a d.a-i
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Step-by-step explanation:
A=
⎣
⎢
⎢
⎡
2
−1
1
−1
2
−1
1
−1
2
⎦
⎥
⎥
⎤
To Prove : A
3
−6A
2
+9A−4I=O
Consider, A
2
=
⎣
⎢
⎢
⎡
2
−1
1
−1
2
−1
1
−1
2
⎦
⎥
⎥
⎤
⎣
⎢
⎢
⎡
2
−1
1
−1
2
−1
1
−1
2
⎦
⎥
⎥
⎤
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