Math, asked by jon888, 10 months ago

Consider the molecules: BF3, PF3, BrF3, SF4, and SF6

(i) Which bonds that are the most polar?explain (considering each bond in molecules)​

Answers

Answered by beastboy1
0

Answer:

BF3 Is most polar

because it has most elctronegativity

Answered by poojanbhatt
2

Step-by-step explanation:

The compounds are. To find which compound is more polar, calculate the electronegativity difference for each molecule. The compound with higher value of will have the higher polar bond.

The electronegativity values of the elements B and F are 2.0 and 4.0 respectively.

en diff = 4-2 = 2

The electronegativity values of the elements P and F are 2.1 and 4.0 respectively.

en diff = 4.-2.1 =1.9

The electronegativity values of the elements Br and F are 2.8 and 4.0 respectively.

en difd = 4-.28= 1.2

The electronegativity values of the elements S and F are 2.5 and 4.0 respectively.

= 4-2.5 =1.5

The electronegativity values of the elements S and F are 2.5 and 4.0 respectively.

=4-2.5=1.5

Therefore, the compound BF3 has most polar bonds because of higher value of EN

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