Math, asked by jeanette6059, 15 days ago

Consider the multiple of 7 in betweenConsider the multiple of 7 in between 100 and 500
1. What are the first and last
2. How many terms are there in the sequence

Answers

Answered by yeolekarprasad91
2

Step-by-step explanation:

Between 100 and 500

15 X 7 = 105

16 X 7 = 112

:

:

71 X 7 = 497 or 500/ 7 = quotient 71 , remainder 3 then we subtract 3 from 500 and get 497.

AP 105, 112, 119, ……. 497.

we use nth trem formula of AP

An = a + ( n - 1 ) d

where a= 105, n= ?, d= 112 -105 = 7 , An = 497

497 = 105 + (n - 1) 7

497–105 = ( n -1 ) 7

392/7 = n-1

56 + 1 = n

n = 57

57 numbers are divisible by 7 between 100 and 500 .

Similar questions