Consider the multiplicative group g = {1,-1, i,- i } and h= {-l,1 } be subgroup of g, then write all possible cosets of h.
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h = 1 h = ( -1 ) h = { 1, -1 } is one coset.
i h = ( -i ) h = { i, -i } is the only other coset.
These are all of the coset because we have now covered all the elements of the group g.
Alternatively, # cosets = (order of group) / (order of subgroup) = 4 / 2 = 2.
N.B. These are left cosets. But since g is an abelian group, the right cosets are the same things.
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. Is the group G = {1, -1, i, i} a normal group?
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