Question

consider the number 4n where n is a natural number check whether there is any value of n for which 4n ends with the digit zero​

Answer 1

Answer:

To be end with the digit zero

it should have 2 and 5 as factors

4^n

(2^2)^n

So here 2 is the only factor and 5 is not a factor. so 4^n won't end with the digit zero