Consider the number 4n , where n is a natural number. Check whether there is any value of e N for which 4n ends with the digit zero
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Answer:
For the number 4
n
to end with digit zero for any natural number n, it should be divisible by 5. This means that the prime factorisation of 4
n
should contain the prime number 5.But it is not possible because 4
n
=(2)
2n
so 2 is the only prime in the factorisation of 4
n
. Since 5 is not present in the prime factorization, so there is no natural number n for which 4
n
ends with the digit zero.
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