Consider the number 6^n where n is a natural number . Check whether there is any value of n ∈ N for which 6^n is divisible by 7
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6^n can be written as 2^n*3^n
no factor of 7 is visible (7is a prime number and if was a factor,it would get reflected in the prime factorisation)
hence no value of n satisfies it
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